1908 United States presidential election in Delaware
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 County Results
Taft 40-50% 50-60%
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| Elections in Delaware |
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The 1908 United States presidential election in Delaware took place on November 3, 1908. All contemporary 46 states were part of the 1908 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.
Delaware was won by the Republican nominees, former Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate John W. Kern. Taft won the state by a margin of 6.16%.
Bryan had previously lost Delaware to William McKinley in both 1896 and 1900.
Results
| 1908 United States presidential election in Delaware[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | William Howard Taft | 25,014 | 52.10% | 3 | |
| Democratic | William Jennings Bryan | 22,055 | 45.94% | 0 | |
| Prohibition | Eugene W. Chafin | 670 | 1.40% | 0 | |
| Social Democratic | Eugene V. Debs | 239 | 0.50% | 0 | |
| Independence | Thomas L. Hisgen | 29 | 0.06% | 0 | |
| Totals | 48,007 | 100.00% | 3 | ||
| Voter turnout | — | ||||
Results by county
| County | William Howard Taft Republican |
William Jennings Bryan Democrat |
Various candidates Others |
Total votes | |||
|---|---|---|---|---|---|---|---|
| % | # | % | # | % | # | ||
| Kent | 49.75% | 4,158 | 49.00% | 4,095 | 1.25% | 104 | 8,357 |
| New Castle | 52.29% | 14,979 | 45.26% | 12,964 | 2.45% | 701 | 28,644 |
| Sussex | 53.25% | 5,870 | 45.48% | 5,013 | 1.27% | 140 | 11,023 |
See also
Notes
References
- ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
