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1998 Gold Flake Open – Doubles

Doubles
1998 Gold Flake Open
Final
ChampionsIndia Mahesh Bhupathi
India Leander Paes
Runners-upFrance Olivier Delaître
Belarus Max Mirnyi
Score6–7, 6–3, 6–2
Events
Singles Doubles
← 1997 · Gold Flake Open · 1999 →

Mahesh Bhupathi and Leander Paes were the defending champions. They successfully defended their title, defeating Olivier Delaître and Max Mirnyi in the final 6–7, 6–3, 6–2.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Australia T Woodbridge
Australia M Woodforde
6 6  
  United States D DiLucia
Australia P Tramacchi
2 2   1 Australia T Woodbridge
Australia M Woodforde
6 1  
WC Germany L Burgsmüller
Germany R Schüttler
6 1 1   France A Clément
France J Golmard
7 6  
  France A Clément
France J Golmard
4 6 6   France A Clément
France J Golmard
3 2  
4 France O Delaître
Belarus M Mirnyi
6 6   4 France O Delaître
Belarus M Mirnyi
6 6  
WC India H Mankad
India G Natekar
1 2   4 France O Delaître
Belarus M Mirnyi
6 3 6
  Italy M Ardinghi
Italy V Santopadre
6 6     Italy M Ardinghi
Italy V Santopadre
3 6 2
  United Kingdom A Richardson
South Africa M Wakefield
2 1   4 France O Delaître
Belarus M Mirnyi
7 3 2
WC India S Kirtane
India V Uppal
2 4   2 India M Bhupathi
India L Paes
6 6 6
  United Kingdom B Cowan
Switzerland F Veglio
6 6     United Kingdom B Cowan
Switzerland F Veglio
2 6 7
Q South Africa D Nainkin
South Africa W Whitehouse
7 6   Q South Africa D Nainkin
South Africa W Whitehouse
6 4 6
3 United States J Salzenstein
United States J Stark
6 4     United Kingdom B Cowan
Switzerland F Veglio
6 1 6
  Czech Republic P Luxa
Israel E Ran
6 6   2 India M Bhupathi
India L Paes
2 6 7
  Germany M Hilpert
United States J Thomas
0 2     Czech Republic P Luxa
Israel E Ran
6 2 3
  Netherlands S Groen
Romania A Pavel
3 6 5 2 India M Bhupathi
India L Paes
3 6 6
2 India M Bhupathi
India L Paes
6 3 7