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1900 Maine gubernatorial election

1900 Maine gubernatorial election
← 1898 September 10, 1900 1902 →
 
Nominee John Fremont Hill Samuel L. Lord
Party Republican Democratic
Popular vote 73,470 40,086
Percentage 62.33% 34.01%
County results
Hill:      40–50%      50–60%      60–70%      70–80%
Governor before election

Llewellyn Powers
Republican

Elected Governor

John Fremont Hill
Republican

The 1900 Maine gubernatorial election took place on September 10, 1900.

Incumbent Governor Llewellyn Powers did not seek re-election. Republican candidate John Fremont Hill defeated Democratic candidate Samuel L. Lord.

General election

Candidates

Major party candidates

Other candidates

Results

1900 Maine gubernatorial election[1][2][3][4][5][6]
Party Candidate Votes % ±%
Republican John Fremont Hill 73,470 62.33%
Democratic Samuel L. Lord 40,086 34.01%
Prohibition Grant Rogers 3,648 3.09%
Socialist Norman Wallace Lermond 643 0.55%
Scattering 21 0.02%
Majority 33,384 28.32%
Turnout 117,878
Republican hold Swing

References

  1. ^ "ME Governor, 1900". Our Campaigns. Retrieved September 29, 2021.
  2. ^ Guide to US Elections, Fifth Edition, Volume II. CQ Press. 2005. p. 1499. ISBN 978-1-56802-981-8. Retrieved September 29, 2021.
  3. ^ Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 126–127. ISBN 0-930466-17-9.
  4. ^ Dubin, Michael J. (2010). United States Gubernatorial Elections, 1861-1911. Jefferson, NC: McFarland & Co. p. 23. ISBN 978-0-7864-4722-0.
  5. ^ Kallenbach, Joseph E.; Kallenbach, Jessamine S., eds. (1977). American State Governors, 1776-1976. Vol. I. Dobbs Ferry, N.Y.: Oceana Publications, Inc. p. 244. ISBN 0-379-00665-0.
  6. ^ Maine Register, State Year-Book and Legislative Manual. Vol. 55. Portland, Maine: Portland Directory Company. 1924. p. 273.


Quelle: https://en.wikipedia.org/wiki/1900_Maine_gubernatorial_election